🔗 Problem #1008

Given two integers $A$ and $B$, write a program that outputs $A / B$.

The first line gives $A$ and $B$. $(0 < A, B < 10)$

Print $A / B$ on the first line. It's correct as long as the absolute or relative error between the actual answer and the output value is at most $10^{-9}$.

• Input

TC
1 3

• Output

TC
0.33333333333333333333333333333333

Allowing an error of up to $10^{-9}$ doesn't necessarily mean you must print exactly to the 9th decimal place.

• Input

TC
4 5

• Output

TC
0.8

An arithmetic problem following Baekjoon 1000 A + B and Baekjoon 1001 A - B. Hard to get wrong.

For JAVA, just be careful that when you divide with int, only the integer portion is returned, so you must declare the values as a floating-point type such as double before dividing.

JAVA
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

/**
 * Baekjoon problem #1008 algorithm class
 *
 * @author RWB
 * @see <a href="https://blog.itcode.dev/posts/2021/06/09/a1008">1008 solution</a>
 * @since 2021.06.09 Tue 10:23:59
 */
public class Main
{
	/**
	 * Main function
	 *
	 * @param args: [String[]] arguments
	 *
	 * @throws IOException data input/output exception
	 */
	public static void main(String[] args) throws IOException
	{
		BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
		
		String[] line = reader.readLine().split(" ");
		
		double a = Double.parseDouble(line[0]);
		double b = Double.parseDouble(line[1]);
		
		System.out.println(a / b);
		
		reader.close();
	}
}

• Math
• Implementation
• Arithmetic